Integrand size = 19, antiderivative size = 96 \[ \int \left (a+\frac {b}{x}\right )^p \left (c+\frac {d}{x}\right )^q \, dx=-\frac {b \left (a+\frac {b}{x}\right )^{1+p} \left (c+\frac {d}{x}\right )^q \left (\frac {b \left (c+\frac {d}{x}\right )}{b c-a d}\right )^{-q} \operatorname {AppellF1}\left (1+p,-q,2,2+p,-\frac {d \left (a+\frac {b}{x}\right )}{b c-a d},\frac {a+\frac {b}{x}}{a}\right )}{a^2 (1+p)} \]
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Time = 0.05 (sec) , antiderivative size = 96, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.158, Rules used = {382, 142, 141} \[ \int \left (a+\frac {b}{x}\right )^p \left (c+\frac {d}{x}\right )^q \, dx=-\frac {b \left (a+\frac {b}{x}\right )^{p+1} \left (c+\frac {d}{x}\right )^q \left (\frac {b \left (c+\frac {d}{x}\right )}{b c-a d}\right )^{-q} \operatorname {AppellF1}\left (p+1,-q,2,p+2,-\frac {d \left (a+\frac {b}{x}\right )}{b c-a d},\frac {a+\frac {b}{x}}{a}\right )}{a^2 (p+1)} \]
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Rule 141
Rule 142
Rule 382
Rubi steps \begin{align*} \text {integral}& = -\text {Subst}\left (\int \frac {(a+b x)^p (c+d x)^q}{x^2} \, dx,x,\frac {1}{x}\right ) \\ & = -\left (\left (\left (c+\frac {d}{x}\right )^q \left (\frac {b \left (c+\frac {d}{x}\right )}{b c-a d}\right )^{-q}\right ) \text {Subst}\left (\int \frac {(a+b x)^p \left (\frac {b c}{b c-a d}+\frac {b d x}{b c-a d}\right )^q}{x^2} \, dx,x,\frac {1}{x}\right )\right ) \\ & = -\frac {b \left (a+\frac {b}{x}\right )^{1+p} \left (c+\frac {d}{x}\right )^q \left (\frac {b \left (c+\frac {d}{x}\right )}{b c-a d}\right )^{-q} F_1\left (1+p;-q,2;2+p;-\frac {d \left (a+\frac {b}{x}\right )}{b c-a d},\frac {a+\frac {b}{x}}{a}\right )}{a^2 (1+p)} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(206\) vs. \(2(96)=192\).
Time = 0.46 (sec) , antiderivative size = 206, normalized size of antiderivative = 2.15 \[ \int \left (a+\frac {b}{x}\right )^p \left (c+\frac {d}{x}\right )^q \, dx=\frac {b d (-2+p+q) \left (a+\frac {b}{x}\right )^p \left (c+\frac {d}{x}\right )^q x \operatorname {AppellF1}\left (1-p-q,-p,-q,2-p-q,-\frac {a x}{b},-\frac {c x}{d}\right )}{(-1+p+q) \left (-b d (-2+p+q) \operatorname {AppellF1}\left (1-p-q,-p,-q,2-p-q,-\frac {a x}{b},-\frac {c x}{d}\right )+x \left (a d p \operatorname {AppellF1}\left (2-p-q,1-p,-q,3-p-q,-\frac {a x}{b},-\frac {c x}{d}\right )+b c q \operatorname {AppellF1}\left (2-p-q,-p,1-q,3-p-q,-\frac {a x}{b},-\frac {c x}{d}\right )\right )\right )} \]
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\[\int \left (a +\frac {b}{x}\right )^{p} \left (c +\frac {d}{x}\right )^{q}d x\]
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\[ \int \left (a+\frac {b}{x}\right )^p \left (c+\frac {d}{x}\right )^q \, dx=\int { {\left (a + \frac {b}{x}\right )}^{p} {\left (c + \frac {d}{x}\right )}^{q} \,d x } \]
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\[ \int \left (a+\frac {b}{x}\right )^p \left (c+\frac {d}{x}\right )^q \, dx=\int \left (a + \frac {b}{x}\right )^{p} \left (c + \frac {d}{x}\right )^{q}\, dx \]
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\[ \int \left (a+\frac {b}{x}\right )^p \left (c+\frac {d}{x}\right )^q \, dx=\int { {\left (a + \frac {b}{x}\right )}^{p} {\left (c + \frac {d}{x}\right )}^{q} \,d x } \]
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\[ \int \left (a+\frac {b}{x}\right )^p \left (c+\frac {d}{x}\right )^q \, dx=\int { {\left (a + \frac {b}{x}\right )}^{p} {\left (c + \frac {d}{x}\right )}^{q} \,d x } \]
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Timed out. \[ \int \left (a+\frac {b}{x}\right )^p \left (c+\frac {d}{x}\right )^q \, dx=\int {\left (a+\frac {b}{x}\right )}^p\,{\left (c+\frac {d}{x}\right )}^q \,d x \]
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